A battery with an emf of 10.4 V and internal resistance of 1.02 carries a positi

Question

A battery with an emf of 10.4 V and internal resistance of 1.02 carries a positive current of 0.505 A from its negative terminal to its positive terminal.

(a) How long is required for 1.09 C of charge to pass through the battery? 2.16s

(b) By how much will the electrical potential energy of 1.09 C of charge increase in crossing the battery terminals?

(c) By how much will the chemical energy decrease?

(d) How much electrical power is supplied by the battery?

(e) At what rate is chemical energy used?

***please answer (b) (c) (d) (e)

Explanation / Answer

Work done = Potential difference × charge = 10.4 *1.09 = 11.34 Joules , hence

b) Hence electrical potential energy of charge will increase by 11.34 Joules

c) Since energy is conserved the increase in electrical potential energy of charge is provided by work done in chemical process hence decrease in chemical energy will be 11.34 joules

d) Power supplied by battery = Votage * current = 10.4 * 0.505 = 5.25 Watt

e) By Energy conservation rule the rate of consumption of energy(i.e. power will be equal to power supplied by chemical i.e. 5.25 Watt

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