Three charged particles form a triangle: particle 1 with charge Q_1 = 102.0 nC i

Question

Three charged particles form a triangle: particle 1 with charge Q_1 = 102.0 nC is at xy coordinates (0, 5.90 mm), particle 2 with charge Q2 is at (0, -5.90 mm), and particle 3 with charge q = 46.0 nC is at (5.90 mm, 0). What are the x component and the y component of electrostatic force on particle 3 due to the other two particles if Q_2 is equal to 102.0 nC? What are the x component and the y component of electrostatic force on particle 3 due to the other two particles if Q_2 is equal to -102.0 nC, ?

Explanation / Answer

(a) Q1 =102 nC , (0.5.9 mm)

Q2 =102 nC , (0.-5.9 mm) , q = 46 nC ,(5.9 mm, 0)

F = kq1q2/r^2

r = ((5.9)^2+(5.9)^2)^0.5 =8.344 mm

F13 = (9*10^9*102*10^-9*46*10^-9)/(8.344*8.344*10^-6) = 0.606 N

F13 = 0.606 cos(45) i - 0.606 sin(45)j

F13 = 0.4285 i - 0.4285 j

F23 = 0.606 N

F23 = 0.4285 i +0.4285 j

F3 = (0.4285 i - 0.4285 j) +(0.4285 i + 0.4285 j)

F3 = 0.857 i

(a) Fx =0.857 N

(b) Fy = 0

(c) Q2 =-102 nC

F13 = 0.4285 i - 0.4285 j

F23 = - 0.4285 i - 0.4285 j

F3 = (0.4285 i - 0.4285 j) +(- 0.4285 i - 0.4285 j)

F3 = 0.857 j

(c) Fx = 0

(d) Fy =0.857 N

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.