A 2.53-muF capacitor is charged to 747 V and a 6.83-muF capacitor is charged to

Question

A 2.53-muF capacitor is charged to 747 V and a 6.83-muF capacitor is charged to 578 V. These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. What will be the potential difference across each and the charge on each? Determine the potential difference across the first capacitor. Express your answer using three significant figures and include the appropriate units. Part B Determine the potential difference across the second capacitor. Express your answer using three significant figures and include the appropriate units. Part C Determine the charge across the first capacitor. Express your answer using three significant figures and include the appropriate units. Part D Determine the charge across the second capacitor. Express your answer using three significant figures and include the appropriate units.

Explanation / Answer

before connecting

Q1 = C1*V1

Q2 = C2*V2

after connecting

Q1' + Q2' = Q1 + Q2

V*(C1+C2) = C1*V1+ C2*V2

V = (C1*V1) + (C2*v2))/(C1+C2)

V = ((2.5*10^-6*747)+(6.8*10^-6*578))/(2.5*10^-6 + 6.8*10^-6))

V = 623.43 V

part A

v1 = 623.43 V

part B

v2 = 623.43 V

part C

Q1' = C1*V = 2.5*10^-6*623.43 = 1558.575 uC

part D

Q2' = C2*V = 6.8*10^-6*623.43 = 4239.324 uC

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