The figure shows a model of a crane that may be mounted on a truck. A rigid unif

Question

The figure shows a model of a crane that may be mounted on a truck. A rigid uniform horizontal bar of mass m1 = 150 kg and length L = 5.8 m is supported by two vertical massless strings. String A is attached at a distance d = 2 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3440 kg is supported by the crane at a distance x = 4.3 m from the left end of the bar.

a) What is the tension in string A?

b) What is the tension in string B?

Explanation / Answer

Sum torque about string B ====> Ta*d - m1*g*L/2 - m2*g*x=0
Ta=g*(m1*L/2+m2*x)/d
Ta=9.81*(150*5.8/2 + 3440*4.3)/2 = 74688.44 N

for Tb, sum forces in the y ======> 74688.44 - Tb - g*3590=0 ========> Tb = 39470.54 N

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