An 84 mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in dia

Question

An 84 mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil is tightly wound around the solenoid at its center. The coil resistance is 9 ohms. The mutual inductance of the solenoid at its center. The coil given instant, the current in the solenoid is 330mA, and is decreasing at the rate of the 2.5 A/S. At the given instant, the induced current in the coil is closest to: 12 mu A 9.0 mu A 6.0 mu A 7.5 mu A 11 mu A A series circuit contains an 80 mu F capacitor, a 20 mH inductor, and a switch. The resistance of the circuit is negligible. Initially, the switch is open, the capacitor voltage is 50 V, and the magnetic energy of the inductor is zero. At time t = 0 the switch is closed. In the situation above, the maximum current in the circuit is closest to: 2.4 A 2.8 A 3.0 A 3.2 A 2.0 A A very long solenoid has 1400 turns per meter, length 620 m, carries current I = 390 A, and each turn is a circle of radius 0.720 m. Inside the solenoid is a small circular coil with 55 turns, each turn of radius 0.350 m. The plane of the coil is the same as the plane of the solenoid. Find magnetic field strength inside the solenoid Find the magnetic flux that passes through the small coil Suppose now that current I in the solenoid is turned off, and it dro at a steady rate from/= 390 A to/= 0 A in 0.330 s. Find epsilon, the EMF induced in the coil. Find mutual inductance of the two solenoids

Explanation / Answer

14)

since there i no resistance, magnetic energy = indutor energy

cv^2 = li^2

i^2 = 80*10^-6* 50*50/20*10^-3

i^2 = 10

i = 3.16 A

i=3.2 A

D Option.

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