An electron moves along the z -axis with v z =3.7×107m/s. As it passes the origi

Question

An electron moves along the z-axis with vz=3.7×107m/s. As it passes the origin, what are the strength and direction of the magnetic field at the following (x, y, z) positions?

Part A

(2 cm , 0 cm, 0 cm)

Express your answers using two significant figures.Enter your answers numerically separated by commas.Bx, By, Bz =

Part B

(0 cm, 0 cm, 2 cm )

Express your answers using two significant figures. Enter your answers numerically separated by commas.Bx, By, Bz =

Part C

(0 cm, 1 cm , 2 cm )

Express your answers using two significant figures. Enter your answers numerically separated by commas.Bx, By, Bz =

Explanation / Answer

Since the electron is passing through +Z-axis.According to Fleming's right hand rule

the direction of the B is along +X-axis

q*v*B = m*g

B = m*g/(q*v) = (9.11*10^-31*9.81)/(1.6*10^-19*3.7*10^7)

Bx = 15.1*10^-19 T

By = 0 T

BZ= 0 T

B) Bx = 0 T

By = 0 T

Bz = 0 T

C) Bx = 0 T

By = 0 T

Bz = 0 T

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