A beaker of water sits in the sun until it reaches an equilibrium temperature of

Question

A beaker of water sits in the sun until it reaches an equilibrium temperature of 30°C. The beaker is made of 100 g of aluminum and contains 180 g of water. In an attempt to cool this system, 100 g of ice at 0°C is added to the water. (a) Determine the final temperature of the system. If Tf = 0°C, determine how much ice remains. (b) Repeat your calculations for 50 g of ice.

Part B: if the aluminum cup has twice the mass but the same valume, how many grams of ice could be melted?

a. 76 g

100 g

84 g

none of the other answers is correct

a. 76 g

100 g

84 g

none of the other answers is correct

Explanation / Answer

here ,

temperature , T1 = 30 degree C

T1 = 303 K

mass of aluminium , mal = 100 gm

mass of water, mw = 180 gm

mass of ice , mi = 100 gm

a) let the mass of ice remaining is m

900 * 0.100 * (30 - 0) + 4186 * 0.180 * (30 - 0) = (100 - m ) * 334

solving for m

m = 24.2 gm

the mass of ice left is 24.2 gm

part B)

for the double mass of the aluminium ,

let the mass of ice melted is m

2 * 900 * 0.100 * (30 - 0) + 4186 * 0.180 * (30 - 0) = m * 334

solving for m

m = 83.8 gm

the mass of ice melted is 83.8 gm = d) 84 gm

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