A starship Naperville is moving at 0.71*c (0.71 times the speed of light) with r
ID: 1469807 • Letter: A
Question
A starship Naperville is moving at 0.71*c (0.71 times the speed of light) with respect to the earth. Using clocks on board the Naperville, its Captain measures the time interval between two events on earth as 33 hrs. A second starship, Glenbard, is moving parallel to the first ship but with a speed of 0.91*c with respect to the earth.
a). If she used clocks on board her ship, what would the Captain of the Glenbard measure the time interval between the events to be?
t{b} c =
Please Show All Work. Thank You in Advance.
Explanation / Answer
let
v1 = 0.71*c
v2 = 0.91*c
t1 = 33 hours
t2 = ?
let to is the time interval measured by observer on the earth.
Use time dialation equation
t1 = to/sqrt(1 - (v1/c)^2)
t2 = to/sqrt(1 - (v12/c)^2)
t2/t1 = sqrt(1 - (v1/c)^2)/sqrt(1 - (v2/c)^2)
= sqrt(1 - 0.71^2)/sqrt(1 - 0.91^2)
= 1.698
t2 = 1.698*t1
= 1.698*33
= 56.034 hours <<<<<<<<------------Answer
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.