A starship Naperville is moving at 0.67*c (0.67 times the speed of light) with r

Question

A starship Naperville is moving at 0.67*c (0.67 times the speed of light) with respect to the earth. Using clocks on board the Naperville, its Captain measures the time interval between two events on earth as 34 hrs. A second starship, Glenbard, is moving parallel to the first ship but with a speed of 0.88 c with respect to the earth.

If she used clocks on board her ship, what would the Captain of the Glenbard measure the time interval between the events to be??????

So I used:

delta t is = delta t (0)/ square root of 1-v^2/c2 (then I did .88-.67 to get .21)
so i did 34/square root of 1-.21c^2/c^2 and got 34.77 hours, but it did not accept it. Can anyone point out if I used the right formula or did the subraction wrong??

These were the hints I got:

HELP: Who measures the "proper time" interval between the two events? The captain of the Glenbard? The Captain of the Naperville? Or someone else?
HELP: Given the information you have, what is that proper time?
HELP: How is the time measured by the Captain of the Glenbard related to the proper time?

Explanation / Answer

The second ship will measure 53.14 hours.

You need the proper time, the time on earth. The formula for time dilation is t' = t. Since the first ship is moving at 0.67c, its gamma is 1.34705.   So proper time t = t'/ = 25.2403 hours. That is the closest to a "true" time that you can get.

Given that proper time, the second ship has a gamma of 2.1054. Using the first formula above, the proper time times that is 53.14 hours.

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