With detailed solution please. The electric force due to a uniform external elec

Question

With detailed solution please.
The electric force due to a uniform external electric field causes a torque of magnitude 10.0 Times 10^-9 N. m on an electric dipole oriented at 30 degree from the direction of the external field. The dipole moment of the dipole is 6.0 Times 10^-12 C m. What is the magnitude of the external electric field? Express your answer with the appropriate units. If the two particles that make up the dipole are 2.5 mm apart. What is the magnitude of the change on each particle?

Explanation / Answer

given

Torque, T = 10*10^-9 N.m

Dpole moment, P = 6*10^-12 C.m

theta = 30 degrees

a) LEt E is the electric field,

we know, T = P*E*sin(theta)

==> E = T/(P*sin(theta))

= 10*10^-9/(6*10^-12*sin(30))

= 3333.3 N/c

b) distance between the two charges, d = 2.5 mm = 2.5*10^-3 m

let q is the magnitude of charge in dipole.

dipole moment, P = q*d

==> q = P/d

= 6*10^-12/(2.5*10^-3)

= 2.4*10^-9 C

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