In the figure, the meterstick\'s mass is 0.145 kg and the string tension is 2.60

Question

In the figure, the meterstick's mass is 0.145 kg and the string tension is 2.60 N . The system is in equilibrium. (Figure 1) when the question was shown in class my professor stated that the strong had a length of 0.7M, the Block .3M and the meter stick has a length of .2M can someone expain why? and how to do the problem.

n the figure, the meterstick's mass is 0.145 kg and the string tension is 2.60 N . The system is in equilibrium.(Figure 1)

Part A

Find the unknown mass m.

Express your answer with the appropriate units.

0.716 kg

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Correct

Part B

Find the upward force the fulcrum exerts on the stick.

Express your answer with the appropriate units.

11.0 N

Figure 1 of 1

n the figure, the meterstick's mass is 0.145 kg and the string tension is 2.60 N . The system is in equilibrium.(Figure 1)

Part A

Find the unknown mass m.

Express your answer with the appropriate units.

0.716 kg

SubmitMy AnswersGive Up

Correct

Part B

Find the upward force the fulcrum exerts on the stick.

Express your answer with the appropriate units.

11.0 N

Figure 1 of 1

Explanation / Answer

Mass of left portion of stick is = 0.3*0.2 = .06 kg

Mass ofright portion of stick is = (1 - 0.3)*0.2 = 0.14 kg

Balancing moments about fulcrum point,

T*(1 - 0.3) + (0.14*9.81)*(1 - 0.3)/2 = mg*0.3 + (0.06*9.81)*(0.3/2)

2.6*0.7 + (0.14*9.81)*(1 - 0.3)/2 = m* 9.81*0.3 + (0.06*9.81)*(0.3/2)

m = 0.751 kg
------------------------------------------

Ny = mg + Mg + T

Ny = (0.751 + 0.145) * 9.8 + 2.6

Ny = 11.38 N

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