In the figure, the point charges arc located at the corners of an equilateral tr

Question

In the figure, the point charges arc located at the corners of an equilateral triangle 22 cm on a side. Part (a) Find the magnitude of the electric field in N/C at the location of q_a, given that q_b = 11.5 mu C and q_c = -43 mu C. |E_a| = Part (b) Find the direction of the electric field at q_a in degrees above the negative x-axis with origin at q_a. Part (c) What is the magnitude of the force in N on q_a, given that q_a = 13 nC? Part (d) What is the direction of the force on q_a in degrees above the negative x-axis with origin at q_a?

Explanation / Answer

a] Electric field = kqb/r^2 + kqc/r^2

= vector sum of 9e9*11.5e-6/0.22^2 +  9e9*4.3e-6/0.22^2 = vector 2138430 and 799587

= sqrt[2138430^2+799587^2 + 2*799587*2138430*cos 120 degree]

= 1871460 N/C ANSWER

b] angle = arctan (2138430 sin 120 degree / ( 799587 + 2138430 cos 120 degree))

= 180-81.7 -60 degree above - x axis

= 38.3 degree above - x axis

c] Force on qA = qE = 1.3e-9*1871460 = 0.002433

d] direction is 38.3 degree above - x axis

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