What is the ˆ? component of the force exerted on the electron by the magnetic fi

Question

What is the ˆ? component of the force exerted on the electron by the magnetic field? Need Help with all 3 questions, do not recall learning about vectors

001 (part 1 of 3) 10.0 points The magnetic field over a certain range is given by B = Blit By J, where B,-7T and By-5 T. An electron moves into the field with a velocity u = vr l+vyjtuz k, where Vz = 4 m/s, t',-9 m/s and uz = 7 m/s. The charge on the electron is-1.602 × What is the î component of the force ex- Answer in units of N 10-19 erted on the electron by the magnetic field? 002 (part 2 of 3) 10.0 points What is the j component of the force? Answer in units of N 003 (part 3 of 3) 10.0 points he force? What is the k component of t Answer in units of N

Explanation / Answer

given that

B = Bxi + Byj

B = 7i + 5j

V = Vxi + Vyj + Vzk

V = 4i + 9j + 7k

charge on electron q = -1.602 * 10^(-19) C

we know that

megnetic force F = q* (V x B)

we will do cross product of V and B

V x B = 28 i x i + 20 i x j + 63 j x i + 45 j x j + 49 k x i + 35 k x j

we know that

cross product of any vector with itself is zero

so , i x i = 0 , j x j = 0

we also know that

i x j = k

j x i = - k

k x i = j

k x j = -i

so,

V x B = 20 k - 63 k + 49 j - 35 i = -43 k + 49 j - 35 i

V x B = -35 i + 49 j - 43 k

so the force on the electron is

F = -1.602*10^(-19) * -35 i + 49 j - 43 k

(a)

i component of force

Fi = -1.602*10^(-19) * -35 i = 56.07*10^(-19) N

(b)

j component of force

Fj = -1.602*10^(-19) * 49 j = - 78.49*10^(-19) N

(c)

k component of force

Fk = -1.602*10^(-19) * - 43 k = 68.88 *10^(-19) N

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.