The figure below shows a top view of a bar that can slide on two frictionless ra

Question

The figure below shows a top view of a bar that can slide on two frictionless rails. The resistor is R = 6.60 , and a 2.50-T magnetic field is directed perpendicularly downward, into the page. Let = 1.20 m. (a) Calculate the applied force required to move the bar to the right at a constant speed of 1.50 m/s. 1.275 Incorrect: Your answer is incorrect. What is the emf induced in the loop formed by the bar, rails and the resistor? N (to the right) (b) At what rate is energy delivered to the resistor? 1.275 Incorrect: Your answer is incorrect. The force Fapp does work on the system. Where does that energy go if the bar moves at constant velocity? W

Explanation / Answer

given data

r = 6.6 ohms

B = 2.5 T

L = 1.2 m

v = 1.5 m/s

a) induced emf = B*v*L

power deliverd to the ckt = power dissipated at resistor

F*v = emf^2/R

F*v = (B*v*L)^2/R

F = B^2*v*L^2/R

= 2.5^2*1.5*1.2^2/6.6

= 2.045 N

induced emf = B*v*L

= 2.5*1.5*1.2

= 4.5 volts

b) Power deliverd to the resistor, P = F*v

= 2.045*1.4

= 2.86 W

This energy converted to heat energy at resistor.

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