A basketball player makes a shot from the free-throw line at a horizontal distan

Question

A basketball player makes a shot from the free-throw line at a horizontal distance of 4.3 m away from the hoop. The hoop is suspended 3.1 m above the ground, and the ball leaves the player's hands 2.2 m above the ground. With a good stopwatch, you determine that it takes the ball 0.55 s to reach the lop of its trajectory, and another 0.36 s to go through the hoop. You have no information about the angle or velocity of the ball, but you decide to make some calculations. Ignore air drag, and assume constant gravitational acceleration equal to 9.8 m/s^2. 4.3 m Which choice best represents the speed of the ball when it is at the top of its trajectory? Zero 4.2 m/4.7 m/s 5.0 m/s None of these Which choice best represents the magnitude of acceleration of the ball when it is at the top of its trajectory? Zero 9.8m/s^2 4.9 m/s^2 20. m/s^2 None of these Which choice best represents the vertical component of the ball's initial velocity? Zero 3.7 m/s 4.9 m/s 5.4 m/s None of these Which choice best represents the initial angle (Go) of the ball's trajectory above horizontal? 45 degree 47 degree 49 degree 51 degree None of these

Explanation / Answer

7)

Let Vertical component of ball's Initial Velocity, = Vi
Time taken to reach top of trajectory, t = 0.55 s
At too of the trajectory, Vertical component of velocity = 0

Vf = Vi - a*t
0 = Vi - 9.8*0.55
Vi = 9.8*0.55 m/s
Vi = 5.39 m/s
Vi = 5.40 m/s
Correct option - (D)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.