A basketball player runs down the court, following the pathindicated by the vect

Question

A basketball player runs down the court, following the pathindicated by the vectors A, B,and C in Figure 3-38. The magnitudes of thesethree vectors are: A = 10.0 m, B = 20.0 m, and C = 7.0 m. Let the+x axis point to the right and the +y axis pointto the far side of the court. (a) Find the magnitude and direction of the net displacementof the player using the component method of vector addition.
1 m
2° (counterclockwise from the +xaxis)
(b) Repeat the previous step, but using the graphical method.Compare your results with those obtained in part (a). (Do this onpaper. Your instructor may ask you to turn in this work.).
Please give as much detail as possible so I can give you ahigh rating thank you! A basketball player runs down the court, following the pathindicated by the vectors A, B,and C in Figure 3-38. The magnitudes of thesethree vectors are: A = 10.0 m, B = 20.0 m, and C = 7.0 m. Let the+x axis point to the right and the +y axis pointto the far side of the court. (a) Find the magnitude and direction of the net displacementof the player using the component method of vector addition.
1 m
2° (counterclockwise from the +xaxis)
(b) Repeat the previous step, but using the graphical method.Compare your results with those obtained in part (a). (Do this onpaper. Your instructor may ask you to turn in this work.).
Please give as much detail as possible so I can give you ahigh rating thank you!

Explanation / Answer

first of all the figure is not visible in your post.
please follow the procedure resolve every vector into components for example first vector 10.0m is making an angle of with X axis its X component is 10cos and Y component is 10sin like wise after resolving all vectors into components add all X components and add all Y components. now the resultant =[X2+Y2]1/2 the direction of the resultant istan=Y/X follow the same procedure on a graph thanks. the direction of the resultant istan=Y/X follow the same procedure on a graph thanks.

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