A 2.00-kg block is pushed against a spring with negligible mass and force consta

Question

A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the block is released, it moves along a frictionless, horizontal surface and then up a frictionless incline with slpe 37.0degree. (a) What is the speed of the block as it slides along the horizontal surface after having left the spring? (b) How far does the block travel up the incline before starting to slide back down? (c) If there is friction between the block and the incline, it travel 0.45 m up the incline. How much work was done by the friction force?

Explanation / Answer

total energy = 0.5 ky2 = 0.5 x 400 x (0.22)2 = 9.68 J

(a) 0.5 mv2 = 9.68 => v = sqrt(2 x 9.68/2) = 3.111 m/s

(b) let height h be travelled, mgh = 9.68 => h = 9.68/(2 x 9.8) = 0.4939 m

or length travelled along incline, L = h/sin37 = 0.8206 m

(c) 9.68 + W = 0.45 x 9.8 x 2 =>   W = - 0.86 J

  

  

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.