In the figure, two 1.39 kg blocks are connected by a massless string over a pull

Question

In the figure, two 1.39 kg blocks are connected by a massless string over a pulley of radius 4.00 cm and rotational inertia 7.40 Times 10^-5 kg-m^2. The pulley is frictionless, but it is unknown whether there is friction between the table and the sliding block. When the system is released from rest, the blocks move with constant acceleration and the pulley turns through 6.28 rad in 0.265 s. The string does not slip on the pulley. Find the tension Ti (in N) in the string where it is attached to the sliding block.

Explanation / Answer

According to the question provided we need to find the tension T2 .

alpha=2*theta/t^2=2(6.28)/(0.265)^2= 178.8536 rad/s^2

a=R*alpha=178.8536 *0.04=7.1514173 m/s^2

T1=m1(g-a1)=1.39(9.8-7.1514173)=3.677735 N

T2=T1-I*alpha/r=3.677735 - (7.40 x10^-5)*(178.8536)/0.04 =3.34685584 N ==============ANSWER)

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