A 5 kg block is hanging from a spring. The spring is supported rigidly from abov

Question

A 5 kg block is hanging from a spring. The spring is supported rigidly from above. The equilibrium position of the block is where the block hangs when it is not oscillating. The block is made to oscillate such that the displacement of the block from its equilibrium position is 0.1 m. The speed of the block is measured, and it is determined that the speed of the block when it passes through the equilibrium position is 1 m/s.

What is the period of oscillations

a. 0.34 s

b. 0.43 s

c. 0.85 s

d. 0.63 s

Explanation / Answer

as speed at equilibrium = Aw = 1 m/s

=> 0.1w = 1

=>0.1 x 2 x 3.14/T = 1

=> T = 0.628 sec = 0.63 s

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