An electron and a proton are fired in opposite directions, and at the instant th

Question

An electron and a proton are fired in opposite directions, and at the instant they are nearest each other, their separation distance is 3.0 m (Figure 1) . At that instant, the two particles are both moving at 5.7×104 m/s but in opposite directions.

Figure 1 of 1

Part A

Determine the magnitude of the magnetic force exerted by the proton on the electron at this instant.

Express your answer with the appropriate units.

Part B

Determine the direction of that force.

Determine the direction of that force.

The magnetic force exerted on the electron is directed into the page. The magnetic force exerted on the electron is directed to the left. The magnetic force exerted on the electron is directed to the right. The magnetic force exerted on the electron is directed upward. The magnetic force exerted on the electron is directed downward. The magnetic force exerted on the electron is directed out of the page.

Explanation / Answer

Magnetic field due to proton at the position of electron, B = (o/4d3)(v x d) = ov/4d2 (out of the page)

Magnetic force on the electron, F = e(v x B) = ov2e/4d2

=> F = (4 * 10-7) * (5.7 * 104)2 * (1.6 * 10-19) / (4 * (3 * 10-6)2) = 5.78 * 10-6 N

This magnetic force is directed towards the right.

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