Very much appreciated. I need help on these homework problems and I\'ve visited
ID: 1509915 • Letter: V
Question
Very much appreciated. I need help on these homework problems and I've visited my schools tutors but they're not confident in any of the help they give me and on some they just tried to "steer" me in the right direction and it wasn't helpful. I need this to study from to really understand this material. Very much appreciated. I need help on these homework problems and I've visited my schools tutors but they're not confident in any of the help they give me and on some they just tried to "steer" me in the right direction and it wasn't helpful. I need this to study from to really understand this material. I need help on these homework problems and I've visited my schools tutors but they're not confident in any of the help they give me and on some they just tried to "steer" me in the right direction and it wasn't helpful. I need this to study from to really understand this material. 7. Light is incident from air onto a material. The incident angle is 52°, and the refracted angle is 25°. What is the polarizing angle for this material?
Explanation / Answer
by Brewster's law
n2 = tan(ip)
using snell's law
n1*sin(i) = n2*sin(r)
1*sin(52) = n2*sin(25)
n2 = sin(52)/sin(25) =1.86
by Brewster's law
n2 = tan(ip)
1.86 = tan(ip)
polarising angle ip = tan^(-1)(1.86)
ip = 61.7 degrees
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