It is desired to use a concave mirror to create an upright image that is 4 times

Question

It is desired to use a concave mirror to create an upright image that is 4 times larger than the object. In terms of the focal length f, at what distance from the mirror should the object be placed? A. 14 C. 314 D. 5174 An object is placed 10 cm from a concave mirr, the image is virtual and three times the size An object is placed 10 cm from a concave mirror, the of the object. What is the focal length of the mirror? A. 7.5 cm B. 15 cm C. 20 cm D. 30 cm The value of the electric field for a certain type of electromagnetic wave is 570 V/m. What is the value of the magnetic field for that wave? 3· A)2.91 x 10*T B) 1.90 x 10 T C) 1.10 x 10*T D) 141 × 10-T E) 2.41 × 10*T In an electromagnetic wave, the value of the peak field compared to the rms field is A. 2 time greater B. 2 times less c. 2 times less D J2 times greater E. None of the above 4. A 36-k2 resistor is in series with a 55-mH inductor and an ac source. What is the impedance of the circuit at source frequency of 3 0 × 10Hz 5. A, 3.0×104 B. 3.7x102 D.50 . What value must C have to produce An LRC circuit has L = 14.8 mH and R = 4.10 resonance at 3600 Hz?. 6. A. 1.3 x 107 F B. 3.7x 10'F C. 50 F

Explanation / Answer

1. m = +4

and m = - di/do = 4

di = - 4do

using mirror equation,

1/f = 1/di + 1/do

1/f = 1/(-4do) + 1/do

1/f = 0.75/do

do = 0.75f

2. m = -di/do = +3

di = -3do = -3 x 10 = -30 cm

1/f = 1/di + 1/do

1/f = 1/-30 + 1/10

f = 15 cm

3. E = vB

B = (570 ) / (3 x 10^8) = 1.9 x 10^-6 T

4. peak = sqrt(2) rms

Ans( D)

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