Two plane mirrors stand facing each other, 2.79 m apart, and a woman stands betw

Question

Two plane mirrors stand facing each other, 2.79 m apart, and a woman stands between them. The woman faces one of the mirrors from a distance of 1.05 m and holds her left arm out to the side of her body with the palm of her left hand facing the closer mirror (a) What is the apparent position of the closest image of her left hand, measured perpendicularly from the surface of the mirror in front of her? m behind the nearer mirror (b) Does it show the palm of her hand or the back of her hand? palm back (c) What is the position of the next image? m behind the nearer mirror (d) Does it show the palm of her hand or the back of her hand? palm back (e) What is the position of the third closest image? m behind the nearer mirror (f) Does it show the palm of her hand or the back of her hand? palm back (g) Which of the images are real and which are virtual? (Select all that apply.) the closest image is real the second closest image is real

Explanation / Answer

dtot= 2.79, d1=1.05, d2=1.74
a) =d1 = 1.05
b)back
c) =d1+2(d2) = 1.05+2*1.74 = 4.53
d)palm
e) = 2(d1+d2) = 2*(1.05+1.74) = 5.58
f)back
g) all virtual

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