Two plane mirrors stand facing each other, 2.79 m apart, and a woman stands betw
ID: 2259311 • Letter: T
Question
Two plane mirrors stand facing each other, 2.79 m apart, and a woman stands between them. The woman faces one of the mirrors from a distance of 1.05 m and holds her left arm out to the side of her body with the back of her hand facing the closer mirror.
(a) What is the apparent position of the closest image of her left hand, measured perpendicularly from the surface of the mirror in front of her? ____________ m behind the nearest mirror.
(b) What is the position of the next closest image? ___________ m behind the nearest mirror
(c) What is the position of the third closest image? ____________ m behind the nearest mirror
Explanation / Answer
Front Distance = BAck Image Distance = 1.05 m
It will show back
Next Closest Image will be at a distance = 1.05+2.79
= 3.84 m behinf the mirror
It will show Palm of the Hand
The Third Closest Image = 3.84+2.79
= 6.63 cm
It will show Back of the Hand
the third closest image is real
the closest image is virtual
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