Consider a charge of +2 nC (nanocoulombs, or Coulombs times 10^-9) at (1, 0), an
ID: 1523500 • Letter: C
Question
Consider a charge of +2 nC (nanocoulombs, or Coulombs times 10^-9) at (1, 0), and a charge of -3 nC at (0, 2). Calculate the electric field strength at the origin. Remember that it is a 2 dimensional vector, and calculate the vector components. Place charges of strength +1 at the points (1, 0) and (-1, 0), and charges of strength -1 at the points (0, 1) and (0, -1). (Units are not important for this problem.) Determine what the field lines would look like for this configuration of charges, using symmetry arguments, and draw a picture of the field lines, with arrows showing the field direction. Remember that field lines flow from positive to negative. No calculations are needed for this problem.Explanation / Answer
3) Net field in X direction = 8.98 * 109 * 2 * 10-9/12
= - 17.96 N/C
Net field in Y direction = 8.98 * 109 * 3 * 10-9/22
= 6.735 N/C
Thus, electric field strength at origin = sqrt(17.962 + 6.7352)
= 19.18 N/C
Thus, vector component = (- 17.96 i + 6.735 j) N/C
4) Electric field lines would start radially from positive charge and end at negative charge .
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