Two large parallel conducting plates carrying opposite charges of equal magnitud

Question

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm.

Part A

If the surface charge density for each plate has magnitude 47.0 nC/m2, what is the magnitude of E  in the region between the plates?

E = ___ N/C

Part B

What is the potential difference between the two plates?

V = ___ V

Part C

If the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the magnitude of the electric field?

[ ] doubles
[ ] stays the same
[ ] halves

Part D

If the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the potential difference?

[ ] doubles
[ ] stays the same
[ ] halves

Explanation / Answer

part A

electric field E = sigma/e0 = 47*10^-9/(8.85*10^-12) = 5310.7 N/C

-------------

part B

potential difference V = E*d

d = seperation = 2.2 cm = 2.2*10^-2 m

V = 5310.7*2.2*10^-2 = 116.8 v

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part C

E does not depend on seperation

so E stays same

---------

part D

V = E*d

as d doubles V also doubles

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