An object whose height is 0.290 cm is at a distance of 14.9 cm from a spherical

Question

An object whose height is 0.290 cm is at a distance of 14.9 cm from a spherical concave mirror. Its image is real and has a height of 0.925 cm. Calculate the radius of curvature of the mirror. How far from the mirror is it necessary to place the above object in order to have a virtual image with a height of 0.925 cm? A dime is on the optical axis of a concave spherical mirror and 38.9 cm away from it. It produces an image on the same side, 8.00 cm away from the mirror. If the dime is moved on the axis to 25.5 cm from the mirror, how far away from the mirror is the image now? What is the radius of the sphere of which the mirror is a section?

Explanation / Answer

12.

ho = object height = 0.290 cm

do = object distance = 14.9 cm

hi = image height = 0.925 cm

di = image distance = ?

using the formula

hi/ho = - di/do

0.925/0.290 = - di/14.9

di = - 47.53 cm

using the mirror equation

1/di + 1/do = 1/f

1/di + 1/do = 2/R

1/(- 47.53) + 1/14.9 = 2/R

R = 43.4 cm

i)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.