In circuit 1, a battery is connected to one resistor R. In circuit 2, two identi
ID: 1529366 • Letter: I
Question
In circuit 1, a battery is connected to one resistor R.
In circuit 2, two identical resistors of resistance R are connected in parallel as a group, and a battery identical to the one in circuit 1 is connected to the group of the two resistors. Which of the following statements comparing the two circuits is true?
The equivalent resistance in circuit 2 is larger than the equivalent resistance in circuit 1.
The voltage across each of the two resistors in Circuit 2 is larger than the voltage across the resistor in circuit 1.
The total electric power consumption in circuit 2 is smaller than the total electric power consumption in circuit 1.
The total current out of the battery in circuit 2 is smaller than the total current out of the battery in circuit 1.
The total current out of the battery in circuit 2 is larger than the total current out of the battery in circuit 1.
a)The equivalent resistance in circuit 2 is larger than the equivalent resistance in circuit 1.
b)The voltage across each of the two resistors in Circuit 2 is larger than the voltage across the resistor in circuit 1.
c)The total electric power consumption in circuit 2 is smaller than the total electric power consumption in circuit 1.
d)The total current out of the battery in circuit 2 is smaller than the total current out of the battery in circuit 1.
e)The total current out of the battery in circuit 2 is larger than the total current out of the battery in circuit 1.
Explanation / Answer
(a) false becuse in second circuit resistors ar connected in parallel to net resistance is
1/ R net = 1/R = 1/R
R net = R/2 <R
(b) false because
The voltage across each of the two resistors in Circuit 2 is same as the voltage across the resistor in circuit 1. due to identical batteries
(c)
True
for circuit 1
P1 = i^2 R
for circuit 2
P2 = i^2 ( R/2) = P1/2
(d) flase
for circuit 1
from the ohm's law
I 1 = V/R
for circuit 2
I2 = V/R/2 = r V/R= 2 I1
(e) True as per above discussion
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