(A brick of mass 1.27 kg is attached to a thin (massless) cable and whirled arou
ID: 1539232 • Letter: #
Question
(A brick of mass 1.27 kg is attached to a thin (massless) cable and whirled around in a circle in a vertical plane. The circle has a radius of 1.48 meters. The cable will break if the tension exceeds 41.0 Newtons. What is the maximum speed the brick can have at the bottom of the circle before the cable will break? (in m/s)2.451 3.2604.336 5.767 7.670 1.020 times 10^1 1 357 times 10^1 1.805 times 10^1 Did you enter your name at the top of this sheet? Did you enter your name and VIP ID on the answer sheet and bubble in your VIP ID with opaque marks? Did you enter the six-digit CODE at the top of this sheet in the CODE field on the answer sheet and bubble it in with opaque marks? I did, I did, I did. Not yet.Explanation / Answer
19
v = speed at bottom
T = tension force = 41 N
m = mass = 1.27 kg
r = radius of circle = 1.48 m
at The bottom , force equation is given as
T - mg = mv2/r
41 - (1.27 x 9.8) = 1.27 v2/1.48
v = 5.76 m/s
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