A 44.5 mA current is carried by a uniformly wound air-core solenoid with 500 tur

Question

A 44.5 mA current is carried by a uniformly wound air-core solenoid with 500 turns, a 11.0 mm diameter, and 14.5 cm length, (a) Compute the magnetic field inside the solenoid. 192.8 mu T (b) Compute the magnetic flux through each turn. differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. T middot m^2 (c) Compute the inductance of the solenoid. mH (d) Which of these quantities depends on the current? (Select all that apply.) magnetic field inside the solenoid magnetic flux through each turn inductance of the solenoid

Explanation / Answer

Solenoid consists of a length of insulated wire coiled into a cylinder shape.

= 192.8 x10^-6 T

B=(permeability of free space)(Number of turns/Length)Current

(b)

magnetic flux is Magnetic fieldx Area = B* * r2

=192.8x10^-6x3.141x(5.5x10^-3)2

= 1.8 x 10^-8 Tm2

(C)

= Lx I

L = 1.8 x 10^-8 / 44.5 x 10^-3

= 4 x 10^-4 mH

(d)

All three quantites depends on current.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.