A movie opens with a beautiful shot of clis over the ocean. A man stands at the

Question

A movie opens with a beautiful shot of clis over the ocean. A man stands at the edge,dressed in a bathing suit, and the camera follows him as he dives, a perfect swan dive. He falls through the air,and suddenly the music shrieks as a giant shark jumps out of the water and bites o his arms. Skeptical, youestimate that the diver is about 10 feet above the water when the shark intercepts him. The shark then landsin the water 5 feet from where it exited the water. At what angle and speed would the shark have needed tojump to devour the character? Assume there are no changes in path due to the collision, and that the sharkbites the diver at the very top of the sharks jump.

Explanation / Answer

from the given data

Hmax = 10 ft = 10*0.3048 = 3.048 m

R = 2*5 = 10 ft = 3.048 m

let vo is the initial speed and theta is the angle of projection.

we know,

Hmax = vo^2*sin^2(theta)/(2*g)

R = vo^2*sin(2*theta)/g

Hmax/R = sin^2(theta)/(2*sin(2*theta))

1 = sin^2(theta)/(2*2*sin(theta)*cos(theta))

1 = tan(theta)/4

theta = tan^-1(4)

= 76 degrees <<<<<<<<<------------Answer

now use,

R = vo^2*sin(2*theta)/g

3.048 = v^2*sin(2*76)/9.8

==> vo = 7.98 m/s <<<<<<<<<------------Answer

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