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Calin College C www.saplinglearning.com ibiscms/mod ibiswiewphp?id 3298466 A hea

ID: 1565678 • Letter: C

Question

Calin College C www.saplinglearning.com ibiscms/mod ibiswiewphp?id 3298466 A heat engine with 0.234 moles of a monatomic p kPa as undergoes the cyclic procedure shown in the pvdiagram on the right. Between stages 3 and 1 the gas is at a constant temperature, and between 2 and 3 no heat is transferred in or ou 525 The temperature of the gas at stage 2 is 365 K. What is the type of each process in the cycle? Between 1 and 2 is isochoric 395 Between 2 and 3 is adiabatic Between 3 and 1 is isothermal What is the temperature between stages 3 and 1? 1350 Number 243.7 What is the work per cycle of this heat engine? Number 172 17 he Web and Mindows V cm 1.60 x 10 Incorrect. scroll down for 2 more questions 5/8/201 Due Date: Points Possible 00 Grade Category: Graded Description: Policies: Brooks You can check your answers You can view solutions after You have ten attempts per q There is no penalty for incor O eTextbook o Help With This Topic o Web Help & Videos O Technical Support and Bu

Explanation / Answer

given

n = 0.234 moles

T ' = 365 K

P ' = 525 X 103 Pa

V ' = 1350 cm3 = 1350 X 10-6 m3  

P = 395 X 103 Pa

T = T ' ( P / P ' )

T = 365 X ( 395 X 103 / 525 X 103 )

T = 274.61 K

V " = 1600 cm3 = 1600 X 10-6 m3  

P " = P V / V "

P " = 395 X 103 X 1350 X 10-6 / 1600 X 10-6

P " = 333.281 kPa

1 ------------- 2 :

W ' = ( n Cv R ) ( T ' - T )

W ' = 0.234 X 1.5 X 8.314 X ( 365 - 274.61 )

W ' = 263.777 J

2 ------------- 3 :

W ' = ( n R / ( - 1 ) ) ( T ' - T )

W ' = ( 0.234 X 8.314 / ( 1.67 - 1 ) ) ( 365 - 274.61 )

W ' = 262.582 J

3 ---------- 1 :

W '' = n R T '' ln ( V / V'' )

W '' = 0.234 X 8.314 X 274.61 X ln ( 1350 / 1600 )

W '' = - 90.76 J

Q '' = W '' = - 90.76 J

Wn = W + W ' + W ''

Wn = 0 + 262.582 - 90.76

Wn = 171.822 J

efficiency = Wn / Q

= 171.822 / 263.777

= 0.6513

= 65.13 %

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