Calin College C www.saplinglearning.com ibiscms/mod ibiswiewphp?id 3298466 A hea
ID: 1614264 • Letter: C
Question
Calin College C www.saplinglearning.com ibiscms/mod ibiswiewphp?id 3298466 A heat engine with 0.234 moles of a monatomic p kPa as undergoes the cyclic procedure shown in the pvdiagram on the right. Between stages 3 and 1 the gas is at a constant temperature, and between 2 and 3 no heat is transferred in or ou 525 The temperature of the gas at stage 2 is 365 K. What is the type of each process in the cycle? Between 1 and 2 is isochoric 395 Between 2 and 3 is adiabatic Between 3 and 1 is isothermal What is the temperature between stages 3 and 1? 1350 Number 243.7 What is the work per cycle of this heat engine? Number 172 17 he Web and Mindows V cm 1.60 x 10 Incorrect. scroll down for 2 more questions 5/8/201 Due Date: Points Possible 00 Grade Category: Graded Description: Policies: Brooks You can check your answers You can view solutions after You have ten attempts per q There is no penalty for incor O eTextbook o Help With This Topic o Web Help & Videos O Technical Support and BuExplanation / Answer
given
n = 0.234 moles
T ' = 365 K
P ' = 525 X 103 Pa
V ' = 1350 cm3 = 1350 X 10-6 m3
P = 395 X 103 Pa
T = T ' ( P / P ' )
T = 365 X ( 395 X 103 / 525 X 103 )
T = 274.61 K
V " = 1600 cm3 = 1600 X 10-6 m3
P " = P V / V "
P " = 395 X 103 X 1350 X 10-6 / 1600 X 10-6
P " = 333.281 kPa
1 ------------- 2 :
W ' = ( n Cv R ) ( T ' - T )
W ' = 0.234 X 1.5 X 8.314 X ( 365 - 274.61 )
W ' = 263.777 J
2 ------------- 3 :
W ' = ( n R / ( - 1 ) ) ( T ' - T )
W ' = ( 0.234 X 8.314 / ( 1.67 - 1 ) ) ( 365 - 274.61 )
W ' = 262.582 J
3 ---------- 1 :
W '' = n R T '' ln ( V / V'' )
W '' = 0.234 X 8.314 X 274.61 X ln ( 1350 / 1600 )
W '' = - 90.76 J
Q '' = W '' = - 90.76 J
Wn = W + W ' + W ''
Wn = 0 + 262.582 - 90.76
Wn = 171.822 J
efficiency = Wn / Q
= 171.822 / 263.777
= 0.6513
= 65.13 %
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