A simple elevator ride can teach you quite a bit about the normal force as this

Question

A simple elevator ride can teach you quite a bit about the normal force as this rider below can (hopefully) tell you. There are three different scenarios given, detailing the rider's experience in an unna each scenario, calculate the normal force, F13, acting on the rider if his mass is m acceleration due to gravity g = 9.81 m/s2. In scenario 1, the elevator has constant velocity. In scenario 2 the elevator is moving with upward acceleration a2 = 3.50 m/s2. Finally, in scenario 3, unfortunately for the rider, the cable breaks and the elevator accelerates downward at a 9.81 m/s2 med or 72.1 kg and the Constant velocitv a2 a, & Number Number N,1

Explanation / Answer

(a)

As the velocity is constant.

so, a = 0

FN1 = mg = 72.1*9.8

FN1 = 707.3 N

(b)

Elevator is accelerating upwards. so, pseudoforce will act down wards

FN2 = m*(g + a2)

FN2 = 72.1*(9.81 + 3.5)

FN2 = 959.65 N

(c)

FN3 = m*(g - a3)

FN3 = 72.1*(9.81 - 9.81)

FN3 = 0

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