A 3-turn coil encloses an elliptical area having a major axis of L = 38.2 cm and

Question

A 3-turn coil encloses an elliptical area having a major axis of L = 38.2 cm and a minor axis of w = 30.4 cm, as seen in the figure. The coil lies in the plane of the page and has an 5.14 A current flowing clockwise in it. If the coil is in a uniform magnetic field of B = 1.99×10-4 T, directed toward the left of the page, what is the magnitude of the torque on the coil? 2.798 10-8 N'm What is the relationship between magnetic field B, magnetic moment and torque T? (Answer: T- × B Hints What kind of product is this? (Answer: vector or cross product.) Which hand do you use to determine the direction of a vector product? what is the magnetic moment of a coil with turns N, current I, and area A? The area of an ellipse is A = nab, where a and b are the semimajor and semiminor axes of the ellipse Submit Answer Incorrect. Tries 1/99 Previous Tries

Explanation / Answer

T = N I A B

A = pi * a * b

torque = 3 * 5.14 * pi * (0.382 / 2) (0.304 / 2) * 1.99 * 10-4

magnitude of torque = 2.79 * 10-4 N.m

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