An object starts at time t = 0 seconds with a velocity of v 0 = +3 m/s and under

Question

An object starts at time t = 0 seconds with a velocity of v0 = +3 m/s and undergoes a constant acceleration of a = -5 m/s2.

1) If the object had initially been moving twice as fast (6 m/s), how far would it have gone before its velocity reached zero? _______ meters

2) Suppose a second object begins moving with a constant speed of v = 3 m/s in the same direction from the same location at the same time as the object in part (4) above. At what time do the paths of these two objects once again cross? _______seconds

PLEASE EXPLAIN STEP BY STEP

Explanation / Answer

1.

using equation of motion

v^2 = u^2 + 2as

{ v is final velocity, u is initial vlocity and s is displacemnt }

0 = 6^2 - 2*5*s

s = 3.6 m

2.)

when both of the object cross again that mean displacement will be same

equting the equation for both the object

s= ut +0.5at^2

3t = 6t -0.5*5 *t^2

t = 1.2 sec

so after 1.2 sec body the object will meet again

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