A battery with an emf of 8 V and an internal resistance of 0.8 is connected to a

Question

A battery with an emf of 8 V and an internal resistance of 0.8 is connected to a variable resistance R. Find the current and power delivered by the battery when R has each of the following values.

1) R 0 n A Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) P W Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 3) R 50 A Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 4) P W Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question.

Explanation / Answer

1)R=0

emf=current*resistance

8=0.8*I

I=10 amp

2)Power=current2*Resistance

P=I2R=10*10*0.8=80W

3)R=5ohm

as two resistance are in series

so Rnet=R+r=5+0.8=5.8 ohm

I=emf/Rnet=8/5.8=1.38V

4)Power=Voltage*current=8*1.38=11.04W

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.