A parallel plate capacitor consists of two plates each of area 12.4 cm 2. . The

Question

A parallel plate capacitor consists of two plates each of area 12.4 cm2.. The distance between the plates is 3.0 mm. There is a vacuum between the capacitor plates. The voltage difference between the plates is (triangle symbol)V=1200 V. A very small sphere with charge q=+1.20 uC and a mass of2.48 x 10-5 kg is placed inside the capacitor next to the positive plate. The sphere is then released from rest. Find the electric field between the capacitor plates. (You may ignore any fringing effects near the edge of the plates.) The answer is either: A. 4.54 x 10-13 V/m B. 3.65 x 10-12 V/m C. 3.60 V/m D. 3.60 kV/m E. 400 kV/m

Explanation / Answer

Using

E = V/d

Where V is potential difference

d is distance between plates

E = 1200/3*10^-3 = 400kV/m

Hence answer is E

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