An 800-kHz radio signal is detected at a point 9.5 km distant from a transmitter

Question

An 800-kHz radio signal is detected at a point 9.5 km distant from a transmitter tower. The electric field amplitude of the signal at that point is 0.23V/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. What is the average electromagnetic energy density at that point? (c = 3.0 times 10^8 m/s, mu_0 = 4 pi times 10^-7 T.middot m/A, elementof_0 = 885 times 10^-12 C^2/N middot m^2) A) 6.6 times 10^-13 J/m^3 B) 9.4 times 10^-13 J/m^3 C) 2.3 times 10^-13 J/m^3 D) 47 times 10^-13 J/m^3 E) 3.3 times 10^-13 J/m^3 16)_____

Explanation / Answer

As average energy density is given by

u = 0.5*0*E02

u = (0.5)(8.85x10-12)(0.23)2

u = 2.3x10-13 J/m3

So the correct option is - C

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