Chrome File Edit View History Bookmarks People Window Help 4)) 80%-- Thu Jul 13

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Chrome File Edit View History Bookmarks People Window Help 4)) 80%-- Thu Jul 13 6:33 PM Nawaf a . . McNeese State U www.saplinglear n x, www.sapinglear x. www. saping earn × (74) Work and ene x O Potential Energy X The Graph Shows x C www.saplinglearning.com/ibiscms/mod/ibis/view.php?id-3805084 Print-Calculator Periodic Table Available From: Due Date: Points Possible Grade Category: Description Policies 100 Question 5 of 20 Map 100 Sapling Learning 100 A cart for hauling ore out of a gold mine has a mass of 441 kg, including its load. The cart runs along a straight stretch of track that is sloped 4.45° from the horizontal. A donkey, trudging along and to the side of the track, has the unenviable job of pulling the cart up the slope with a 412-N force for a distance of 121 m by means of a rope that is parallel to the ground and makes an angle of 13.3° with the track. The coefficient of friction for the cart's wheels on the track is 0.0151. Use g 9.81 m/s' 100 Find the work that the donkey performs on the cart during this process. You can check you You can view solut You can keep tryin Number 100 13.3 you get it right or There is no penalty For multiple-choice track Find the work that the force of performs on the cart during th click to edit rope 100 Number on the number of 100 eTextbook O Help With ThisT OWeb Help & Vid 45 Calculate the work done on the cart during the process by friction track incline horizontal ground Number 100 100 13 ols

Explanation / Answer

Work done = F.d = |F||d| cos(theta)

where theta is the angle between F and d vector.

For work done by donkey:

F = 412 N , d = 121 m

theta = 13.3 deg

W = (412)(121) cos13.3

W = 48514.9 J ........Ans

Work done by gravity :

F = m g

theta = 90+ 4.45

W = (441 x 9.81) (121) cos(90 + 4.45)

W = - 40615.67 J ......Ans

Work done by friction :

48514.9 - 40.615.67 + W = 0

W = - 7900 J ........... Ans

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