A car is traveling around a horizontal circular track with radius r = 220 m as s

Question

A car is traveling around a horizontal circular track with radius r = 220 m as shown. It takes the car t = 51 s to go around the track once. The angle A = 33° above the x axis, and the angle B = 57° below the x axis.

1)What is the magnitude of the car’s acceleration?

2)What is the x component of the car’s velocity when it is at point A

3)What is the y component of the car’s velocity when it is at point A

4)What is the x component of the car’s acceleration when it is at point B

5)What is the y component of the car’s acceleration when it is at point B

6)As the car passes point B, the y component of its velocity is (Increasing,Decreasing, or Constant).

Explanation / Answer

1] speed v = 2pi r /T = 2 pi*220/51 = 27.1 m/s

a = v^2/r = 27.1^2/220

= 3.338 m/s^2 answer

2] Vx = 27.1* sin 33 degree

= 27.19* sin 33 degree

= 14.81 m/s

3] Vy = -27.1* cos 33 degree

= -22.73 m/s

4] ax = -3.338* cos 57 degree

= -1.818 m/s^2

5] ay = 3.338* sin 57 degree

= 2.799 m/s^2

6] increasing because ay is positive

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.