please answer the following question. unuiewiassighmentProblemID-84109763& offse
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please answer the following question.
unuiewiassighmentProblemID-84109763& offset next Homework Exercise 19.6 e previous | 10 of 14 net Exercise 19.6 Part A A gas undergoes two processos. In the first, the volume remains constant at 0.240 m3 and the pressure increases from 3.00×105 Pato 5.00x105 Pa. The second process is a compression to a volume of 0.160 m at a constant pressure of 5.00x10% Pa. Find the total work done by the gas during both processes W- Submit My Answers Give Up Provide Feedback
Explanation / Answer
19.6)
in 1st process, W1 = P(dV)
here Volume is contant, dV = 0 => W1 = 0
in 2nd process, W2 = P(dV) = P(V2 - V1) = 5 x 105 x (0.160 - 0.240) = -40000 J
net work by gas, W = W1 + W2 = -40000 J
19.10) No. of moles = 5 (ideal monoatomic gas)
initial temperature = 132 oC
Q = 1500 J
W = 2400 J
dU = Q - W = 1500 - 2400 = -900 J
nCv(dT) = -900
5 x 1.5R x (T - 132) = -900
T = -(120/8.314) + 132 = 117.56 oC
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