Light travels from a medium (lowest layer) of index of refraction n\'. Then it p

Question

Light travels from a medium (lowest layer) of index of refraction n'. Then it passes into a second medium of a slightly larger index of refraction and it finally makes it out in air (take n_air = 1 Just for vacuum): The ray that correctly shows the light path described above is: a) 1 b) 2 c) 3 d) 4 e) 5 f) I have my own answer (Explain your (a)-to -(f) choice above) Which ray in the figure above shows total internal reflection? a) 1 b) 2 c)3 d) 4 e) 5 f) I have my own answer A method of determining the speed of light in fluids (gasses and liquids) is by using the refraction of light. Rays from a light source, submerged in vegetable oil hit the interface with air at an angle of incidence of 10.5 degree. The refraction angle in air is 15.5 degree. Calculate the speed of light in vegetable oil.

Explanation / Answer

Solution to second question

Given,

theta1 = 10.5 ; theta2 = 15.5 deg ;

We know from Snells law:

n1 sin(theta1) = n2 sin(theta2)

n2 = 1 x sin15.5/sin10.5 = 1.47 (index of refraction of oil)

We know from defination of index of refraction:

n = c/v =>v = c/n

v = 3 x 10^8/1.47 = 2.04 x 10^8 m/s

Hence, speed in oil = v = 2.04 x 10^8 m/s

First question:

(5)

from Snell's law we know that

n1 sin(theta1) = n2 sin(theta2)

theta2 = (n1/n2) sin(theta1)

theta 2 will have less value since n2 > n1

Ray 5 explains it better.

none of them shows total internal reflection since none of them is reflecting back into the same medium.

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