I could use some help with parts B and C please. Astrology, that unlikely and va
ID: 1658417 • Letter: I
Question
I could use some help with parts B and C please.
Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of one's birth. The only known force a planet exerts on Earth is gravitational. (a) Calculate the magnitude of the gravitational force (in N) exerted on a 4.00 kg baby by a 110 kg father 0.150 m away at birth (he is assisting, so he is close to the child.) 0000013N Calculate the magnitude of the force on the baby (in N) due to Jupiter if it is at its closest distance to Earth, some 6.29 x 1011 m away. Other objects in the room and the hospital building also exert similar gravitational forces. (Of course, there could be an unknown force acting, but scientists first need to be convinced that there is even an effect, much less that an unknown force causes it.) .000008054 × N (b) How does the forceupiter on the baby compare to the force of the father on the baby? Ffather FJupiterExplanation / Answer
According to the given problem,
F = G*m*M / d²
for G = 6.674e11N·m²/kg²
(a) F = 6.674e11N·m²/kg² * 4.00kg * 110kg / (0.150m)² = 1.305e-6 N
(b) F = 6.674e11N·m²/kg² * 4.00kg * 1.90e27kg / (6.29e11m)² = 1.30e-6 N
(c) the ration is = 1.018
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