An air-filled parallel plate capacitor (capacitance C) is connected to a battery

Question

An air-filled parallel plate capacitor (capacitance C) is connected to a battery (voltage is fully charged (to charge Qo). Because of being charged up there is an electric field between the plates (Eo) and electrical energy stored between the plates (Uo). While remaining connected to the battery, a dielectric material with a dielectric constant of 3.0 is placed between the plates of the capacitor. What are the new values of the following quantities in terms of the given quantities? 5, until it (a) C (b) Q (c) V (d) E (e) U

Explanation / Answer

a) C0 = e0 ( A)/ d ( in absence of dielectric constant)

C = 3 e0 ( A)/ d = 3 C0 ( in presence of dielectric constant)

b) Q ( in presence of dielectric) = 3 Q00

c) V = V0/3

d) E0 = 1/2 C0V0^2

E= 1/2 ( 3C0) ( V0^2/9) = E0/3

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