An air-filled parallel plate capacitor is connected to a battery and allowed to

Question

An air-filled parallel plate capacitor is connected to a battery and allowed to charge up. Now a slab of dielectric material is placed between the plates of the capacitors while the capacitors is still connected to the battery. After this is done one would find that the voltage across the capacitor had increased. the voltage across the capacitor had decreased. the charge on the capacitor had increased. the charge on the capacitor had decreased. None of these is true. A coil of wire is placed in the X - Y plane with its center on the Z-axis of a solenoid carrying a DC current, as shown in the figure. Which, if any. of the following (A-D) while NOT result in an EMF being induced in the coil? If all will, chose E. Change the current in the solenoid. Rotate the coil about the z-axis. Rotate the coil about the y-axis. Move the coil toward point P. All the A-D actions will cause an EMF to be induced. When using the equation: dB^rightarrow = mu_oIdl^rightarrow x r^rightarrow/4 pi r^2 to find the magnetic field due to a current in a wire, it is important to recognize that this expression must be integrated over all values of r to find the total magnetic field. this expression must be integrated over the total length of the wire to find the total magnetic field. dl^rightarrow is a small element of displacement along an imaginary path surrounding the wire. r^rightarrow is a vector directed from the point at which the field is to be found toward a small element of length on the wire. dB^rightarrow is the change in magnetic field when one moves an additional displacement dr^rightarrow from the wire.

Explanation / Answer

(4). Answer is Charge on the capacitor had increased.

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The voltage across the capacitor remains same when the battery is connected.

The voltage across the capacitor decreases when the battery is disconnected.

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