A small 265-g plastic ball that has a charge q of 1.75 C is suspended by a strin

Question

A small 265-g plastic ball that has a charge q of 1.75 C is suspended by a string that has a length L of 1.00 m in a uniform electric field, as shown in the figure. If the ball is in equilibrium when the string makes a 9.80° angle with the vertical as indicated by 8, what is the electric field strength E? Number 2.78× 10-3 N/ C m,q There is additional feedback available View this feedback by clicking on the bottom divider bar. Click on the divider Incorrect bar again to hide the additional feedback.

Explanation / Answer

Mg= T cos@

QE = Tsin@

2.65*10^-3 *9.81/cos9.8°= T

T=2.635*10^-2

E=T sin@/Q

E= 2.56 * 10^-3.  

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