Chapter 20 tutorials and hints Forces in a Three-Charge Systenm ) 70116 (> Const

Question

Chapter 20 tutorials and hints Forces in a Three-Charge Systenm ) 70116 (> Constants Part A Coulomb's law for the magnitude of the force F between two particles with charges Qand Q separated by a distance d is What is the net force exerted by these two charges on a third charge q 52.0 nC placed between gi and g at 1.195 m? Your answer may be positive or negative, depending on the direction of the force Express your answer numerically in newtons to three signiticant figures. where K =-o, and -8.854 × 10 12 C2/(N·) is the permittivity of free space. where K and View Available Hint(s) ? Consider two point charges located on the x axis: one charge, g 13.5 nC, is located at x1 =-1 665 m : the second charge, q2-33.0 nC is at the origin (a 0.0000). Force on ga 6.53 10 Submit Pr vious Answers XIncorrect Try Again: 3 attempts remaining Next > Provide Feedback

Explanation / Answer

Fnet = F13 + F23

Since F1 and F3 are both negative charge So force will be repulsive and toward +ve x-axis

Since F2 and F3 are both opposite charge So force will be attractive and toward +ve x-axis

F13 = kq1q3/r13^2

r13 = -1.195 - (-1.665) = 0.47 m

F23 = kq2q3/r23

r23 = 0 - (-1.195) = 1.195 m

Fnet = k*q3*(q1/r13^2 + q2/r23^2)

Fnet = 9*10^9*52*10^-9*(13.5*10^-9/0.47^2 + 33*10^-9/1.195^2)

Fnet = 3.94*10^-5 N

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