An electron is moving at a speed of 0.8 x10 4 m/s in a circular path ofradius of

Question

An electron is moving at a speed of 0.8 x104 m/s in a circular path ofradius of 1.9 cm inside a solenoid.The magnetic field of the solenoid is perpendicular to the plane ofthe electron's path. The solenoid has 25 turns per centimeter. (a) Find the strength of the magnetic fieldinside the solenoid.
1 T
(b) Find the current in the solenoid.
2 mA (a) Find the strength of the magnetic fieldinside the solenoid.
1 T
(b) Find the current in the solenoid.
2 mA

Explanation / Answer

Mass of electron = 9.1 x 10-31 kg                        q = 1.6 x 10-19 C                         v = 0.8 x 104 m/s                         r = 1.9 x 10-2 m                         n = 25 x 102 / m a)         We know that             B = mv / qr                = 9.1 x 10-31 * 0.8 x 104 / 1.6 x10-19 * 1.9 x 10-2               = 2.394 T b) We know that            B = o n i      ==> i = B /o n               = 2.394 x 10-6 / 4 x 10-7 * 2500                = 7.626 x 10-4 A                = 0.7626 mA

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