A helicopter, starting at rest, accelerates straight upfrom the roof of a hospit

Question

A helicopter, starting at rest, accelerates straight upfrom the roof of a hospital. The lifting forces does work inraising the helicopter. An 810-kg helicopter rises from rest to aspeed of 7.0 m/s in a time of 3.5s. During this time it climbs to aheight of 8.2m. What is the average power generated by the liftingforce? If you could please lists all the steps that you did tp solvethis that would be so helpful. A helicopter, starting at rest, accelerates straight upfrom the roof of a hospital. The lifting forces does work inraising the helicopter. An 810-kg helicopter rises from rest to aspeed of 7.0 m/s in a time of 3.5s. During this time it climbs to aheight of 8.2m. What is the average power generated by the liftingforce? If you could please lists all the steps that you did tp solvethis that would be so helpful.

Explanation / Answer

The total work done is               W = mgh + 0.5 mv2                    = 810*9.8*8.2 + 0.5 * 810 * 72                    = 84936.6 J Therefore the average power          P = W / t = 24267.6 W

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.